6x^2-4x+3/3x+4+4x^2+1/3x+4

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Solution for 6x^2-4x+3/3x+4+4x^2+1/3x+4 equation: 


x in (-oo:+oo)

6*x^2+4*x^2-(4*x)+(3/3)*x+(1/3)*x+4+4 = 0

6*x^2+4*x^2-4*x+(3/3)*x+(1/3)*x+4+4 = 0

10*x^2-8/3*x+8 = 0

DELTA = (-8/3)^2-(4*8*10)

DELTA = -2816/9

DELTA < 0

x belongs to the empty set

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